NEET-AIPMT 1988 TO 2017 CHAPTER WISE PRACTICE QUESTIONS

NEET-AIPMT 1988 TO 2017 CHAPTER WISE PRACTICE QUESTIONS


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all organic reactions mechanism

http://www.orgmech.co.uk/All.php

TYPES OF WEAK BOND | CHEMICAL BONDING | Inorganic chemistry | NEERAJ DUBEY

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John teller effect

https://youtu.be/8ybR2zoNEg4

Lassaigne's test

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Quantum no for any electron

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Jee practice papers

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JEE/NEET P-BLOCK

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Practice test material for neet

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Important topics and questions

JEE MAIN ADVANCED VIDEO LECTURE LINKS

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https://www.youtube.com/watch?v=aeIWUh0mbMA&list=PLx2L6yjUEa7uAg-2UiupNBXzuX9AeT1CE

Prince Singh

https://www.youtube.com/watch?v=5tHInYkU9uQ

Dushyant Kumar

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chemistry revision plan and videos link

The below link mainly contains Study guides for various topics in JEE Syllabus and Revision material of Chemistry

http://iit-jee-chemistry.blogspot.in/search/label/p-Block%20elements

Video Lectures

http://iitchemvideos.blogspot.in

JEE/ NEET 2016,2017 papers with solutions

https://drive.google.com/drive/folders/1MJGVS3NH--xEmMm-4gfFkWPVlsUxTvk4?usp=sharing

Organic chemistry

JEE / NEET PRACTICE QUESTIONS CHAPTER WISE

https://drive.google.com/file/d/0B0j8xA2-VWfobnVCcVpuM2gtRW1QY1RfaEdudnBIRE1xVlV3/view?usp=drivesdk

Thermodynamics JEE / NEET

First law of thermodynamics:- If the quantity of heat supplied to a system is capable of doing work, then the quantity of heat absorbed by the system is equal to the sum of the increase in the internal energy of the system, and the external work done by it.

dQ = dU+dW

Thermodynamic Process:- A process by which one or more parameters of thermodynamic system undergo a change is called a thermodynamic process or a thermodynamic change.

(a) Isothermal process:- The process in which change in pressure and volume takes place at a constant temperature, is called a isothermal change. It may be noted that in such a change total amount of heat of the system does not remain constant.

(b) Isobaric process:- The process in which change in volume and temperature of a gas take place at a constant pressure is called an isobaric process.

(c) Isochoric process:- The process in which changes in pressure and temperature take place in such a way that the volume of the system remains constant, is called isochoric process.

(d) Adiabatic process:- The process in which change in pressure and volume and temperature takes place without any heat entering or leaving the system is called adiabatic change.

(e) Quasi-static process:- The process in which change in any of the parameters take place at such a slow speed that the values of P,V, and T can be taken to be, practically, constant, is called a quasi-static process.

(f) Cyclic process:- In a system in which the parameters acquire the original values, the process is called a cyclic process.

(g) Free expansion:- Such an expansion in which no external work is done and the total internal energy of the system remains constant is called free expansion.

Reversible isothermal and adiabatic curve:-

  

Application of first law of thermodynamics:-

(a) Cooling caused in adiabatic process:- dT = PdV/C_v

(b) Melting:- dU = mL_f

(c) Boiling:- dU = mL_v – P(V_f -V_i)

(d) Mayer’s formula:- C_p - C_v = R

Specific heat capacity of gases:- Specific heat capacity of a substance is defined as the amount of heat required to raise the temperature of a unit mass of substance through 1ºC.

(a) Specific heat capacity at constant volume (c_v):- Specific heat capacity at constant volume is defined as the amount of heat required to raise the temperature of 1 g of the gas through 1ºC keeping volume of the gas constant.

Molar specific heat capacity, at constant volume (C_v), is defined as the amount of heat required to raise the temperature of 1 mole of gas through 1ºC keeping its volume constant.

C_v= Mc_v

(b) Specific heat capacity at constant pressure (c_p):- Specific heat capacity, at constant pressure, is defined as the amount of heat required to raise the temperature of 1 g of gas through 1ºCkeeping its pressure constant.

Gram molecular specific heat capacity of a gas (C_p), at constant pressure, is defined as the amount of heat required to raise the temperature of 1 mole of the gas through 1ºC keeping its pressure constant.

C_p = Mc_p

Difference between two specific heat capacities – (Mayer’s formula):-

(a) C_p - C_v = R/J

(b) For 1 g of gas, c_p - c_v = r/J

(c) Adiabatic gas constant, γ = C_p/ C_v = c_p/ c_v

Relation of C_v with energy:-

C_v= 1/m (dU/dT)

(a) Mono-atomic gas (3 degree of freedom):-

Total energy, U = mN 3 [(1/2) KT], Here m is the number of moles of the gas and N is the Avogadro’s number.

C_v = (3/2) R

C_p = (5/2) R

γ = C_p/ C_v = 5/3 = 1.67

(b) Diatomic gas:-

At very low temperature, Degree of Freedom (DOF) = 3

U = (3/2) mRT

C_v = (3/2) R,  C_p = (5/2) R

γ= C_p/ C_v = 5/3 = 1.67

At medium temperature, DOF = 5

U = (5/2) mRT

C_v = (5/2) R,  C_p = (7/2) R

γ = C_p/ C_v = 7/5 = 1.4

At high temperature, DOF = 7

U = (7/2) mRT

C_v = (7/2) R,  C_p = (9/2) R

γ = C_p/ C_v = 9/7 = 1.29

Adiabatic gas equation:- PV ^γ = Constant

(a) Equation of adiabatic change in terms of T and V:- TV ^γ-1 = Constant

(b) Equation of adiabatic change in terms of P and T:- T ^γ P^1-γ = Constant

Comparison of slopes of an isothermal and adiabatic:-

(a) Slope of isothermal:- dP/dV = -P/V

(b) Slope of adiabatic:- dP/dV = -γP/V

(c) Adiabatic gas constant:- γ = C_p/C_v

As, C_p>C_v, So, γ>1

This signifies that, slope of adiabatic curve is greater than that of isothermal.

Slope on PV diagram:-

(a) For isobaric process: zero

(b) For isochoric process: infinite

Work done for isobaric process:- W = P(V₂-V₁)

Work done for isochoric process:- W = 0

Work done in isothermal expansion and compression:-

            ?W = 2.3026 RT log₁₀V_f/V_i  (isothermal expansion)

W = - 2.3026 RT log₁₀V_f/V_i  (isothermal compression)

Work done during an adiabatic expansion:-

W = K/1-γ [V_f^1-γ – V_i ^1-γ] = 1/1-γ [P₂V₂-P₁V₁] = R/1- γ [T₂-T₁]

Adiabatic constant (γ):- γ = C_p/C_v = 1+2/f, Here f is the degrees of freedom.

Work done in expansion from same initial state to same final volume:-

W_adiabatic < W_isothermal < W_isobaric

Work done in compression from same initial state to same final volume:-

W_adiabatic < W_isothermal < W_isobaric

Reversible process:- It is a process which can be made to proceed in the reverse direction by a very slight change in its conditions so that the system passes through  the same states as in direct process, and at the conclusion of which the system and its surroundings acquire the initial conditions.

Example:- All isothermal and adiabatic process when allowed to proceed slowly, are reversible, provided there is no loss of energy against any type of resistance. Friction, viscosity are other examples.

Irreversible process:- A process which cannot be made to be reversed in opposite direction by reversing the controlling factor is called an irreversible process.

Example:-

(a) work done against friction

(b) Joule’s heating effect

(c) Diffusion of gases into one another

(d) Magnetic hysteresis

Heat engine:- It is a device used to convert heat into mechanical energy

(a) Work done, W = Q₁-Q₂

(b) Efficiency:- Efficiency η of an engine is defined as the fraction of total heat, supplied to the engine which is converted into work.

η= W/ Q₁ = [Q₁- Q₂]/ Q₁ = 1-[Q₂/Q₁]

Carnot engine – Carnot’s reverse cycle:-

(a) First stroke (isothermal expansion):- W₁= RT₁ log_e[V₂/V₁]

(b) Second stroke (adiabatic expansion):- W₂= R/γ-1 [T₁-T₂]

(c) Third stroke (isothermal compression):- W₃= RT₂ log_eV₃/V₄

(d) Fourth stroke (adiabatic compression):- W₄= R/γ-1 [T₁-T₂]

(e) Total work done in one cycle, W = W₁+ W₂+ W₃+ W₄ = R (T₁-T₂) log_e (V₂/V₁)

Efficiency of Carnot engine:- Efficiency η of an engine is defined as the ratio between useful heat (heat converted into work) to the total heat supplied to the engine.

η = W / Q₁ = [Q₁- Q₂]/ Q₁ = 1-[Q₂/Q₁] = 1- T₂/T₁

Second law of thermodynamics:-

(a) Clausius statement:- Heat cannot flow from a cold body to a hot body without the performance of work by some external agency.

(b) Kelvin’s statement:- It is impossible to obtain a continuous supply of energy by cooling a body below the coldest of its surroundings.

(c) Planck’s statement:- It is impossible to extract heat from a single body and convert the whole of it into work.

Refrigerator:- It is a device which is used to keep bodies at a temperature lower than that of surroundings.

Coefficient of performance (β):-Coefficient of performance of a refrigerator is defined as the amount of heat removed per unit work done on the machine.

β = Heat removed/work done = Q₂/W= Q₂/[Q₁- Q₂] = T₂/[T₁- T₂]

Coefficient of performance of a refrigerator is not a constant quantity since it depends upon the temperature of body from which the heat is removed.

For a perfect refrigerator, W = 0 or Q₁=Q₂ or β =∞

Mean free path:- λ= 1/√2πd²ρ_n

Here ρ_n = (N/V) = number of gas molecules per unit volume

d = diameter of molecules of the gas.

Heat added or removed:-

(a) For isobaric process:- Q = n C_pΔT

(b) For isochoric process:- Q = n C_vΔT

(c)For isothermal process:- Q = nRTlog_e (V₂/V₁)

(d) For adiabatic process: Q = 0

Change in internal energy:-

(a) For isobaric process, ΔU = n C_pΔT

(b) For isobaric process, ΔU = n C_vΔT

(c) For isothermal process, ΔU = 0

(d) For adiabatic process, ΔU = -W = [nR (T₂-T₁)]/(γ-1)

Mixture of gases:- n = n₁+n₂

M = n₁M₁+n₂M₂/ n₁+ n₂ = N₁m₁+N₂m₂/N₁+N₂

and

Enthalpy (H):-

(a) H = U+PV

(b) At constant pressure:-

dH = dU + pdV

(c) For system involving mechanical work only:-

dH = Q_P (At constant pressure)

(d) For exothermic reactions:-

dH is negative

(e) For endothermic reactions:-

dH is positive

Relation between dH and dU:-

dH = dU + dn_g RT

Here, dn_g = (Number of moles of gaseous products - Number of moles of gaseous reactants)

Alkaline earth metals good explanation

https://googleweblight.com/i?u=https://www.chemguide.co.uk/inorganic/group2/properties.html&grqid=RNmEjPJR&hl=en-IN

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